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6(2x-5)=3^2-x
We move all terms to the left:
6(2x-5)-(3^2-x)=0
We multiply parentheses
12x-(3^2-x)-30=0
We get rid of parentheses
12x+x-30-3^2=0
We add all the numbers together, and all the variables
13x-39=0
We move all terms containing x to the left, all other terms to the right
13x=39
x=39/13
x=3
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